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X^2+X^2=22X^2
We move all terms to the left:
X^2+X^2-(22X^2)=0
We add all the numbers together, and all the variables
-20X^2=0
a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$X=\frac{-b}{2a}=\frac{0}{-40}=0$
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